Make a decision. 025= 0.
where in the table the closest (0. 304.
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030. E. 84 3. you can find out more We reject H0 if T is either greater than or
equal to the larger critical value of x or less than the lower
critical value of x.
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975 is 8. Decision Do not reject H 0 We conclude that the two
population dispersion parameters may be equal. , 33(1973),
353-363. .
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(Two-sided)H0 :1 = 2H1 :1 2CASE B. 4. 36 3. The data consist of two random samples and from
populations 1 and 2, respectively. . 625.
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975 is 43. 813. Data on the cardiac index were obtained after
operation. Make hypotheses H0 :1 = 2H1 :1 2(claim)2.
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139. Decision H 0 Do not reject6. 9)If n1 n2 is even, andT* n1 ( n1 n2 12 ) T [ ] 4( n1 n2 ) n1n2 (
n1 n2 1)[3 ( n1 n2 ) 2 ] 48( n1 n2 ) 2(3. One group of dogs was
untreated, and a second group received propranolol 10minutes before the occlusion. 345.
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Assign ranks to the ordered measurements
as follows: the smallest measurement and the largest measurement
are each given a rank of 1. All patients were seen
initially for severe aortic valvular disease requiring prosthetic
valve replacement. 66. 00
2. 36 2.
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301. 243. The two samples are independent. 025 is 20. 8, the value of T for
/2n1 = 10, n2 = 10 and /2 = 0. 244.
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OBrien, Uptake and loss of
14C-dopamine ByPlatelets From Children With Infantile Autism, J. 19 2. recordedthe relative area of necrosis (percentage of fibers
involved) in the posterior papillary muscle of each dogs heart. 122.
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Gordon* et al. 50 2. C. The data are
measured on at least an ordinal scale.
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851. 70 3. 9718)4. The population distribution
are continuous.
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113. The two population are
identical (including equal medians) except a possible difference in
dispersion. 9286) 4. Exercise 2Boullin* and OBrien studied uptake and loss of14C-dopamine by platelets in five autistic children and five normal
controls. Make hypothesesH0 :1 = 2 H1 :1 2 (claim)SOLUTION:2. Let = 0.
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(CASE C)HYPOTHESIS H0 :1 = 2 H1 :1 2REJECT H0T x1 / 2 or T x/2,n1 ,n2H0 :1 2, H1 :1 2T x1 ,n1 ,n2H0 :1 2 H1 :1 2T x , n1 , n2Example. T X T X2125. HYPOTHESES CASE A. * Boullin, David J. *
Gordon, Richard F.
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8, we maycomputeT*n1 ( n1 n2 2) ] 4 n1n2 ( n1 n2 2)( n1 n2 2) [ 48 (n1 n2 1)] T
[(3. 0192) The value
of T for 1-/2 = 0. . 30 2. (CASE B) c.
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339. EXAMPLEEXERCISE 1EXERCISE 2LARGE – SAMPLE APPROXIMATION When the sample sizes exceed those
found in Table A. Your Domain Name MAKE A DECISION. 025 According to the table A.
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97 2. studied the effect of propranolol on
the severity of myocardial necrosis following 40 minutes of
temporary coronary-artery occlusion in dogs. We reject H0 if T is less than the
critical value of x. 00 Group 2 (y) 3.
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TABLE A. 70 3. Exercise 1Reimer* et al. 422.
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ASSUMPTIONSA. 50 2. We compute T * for significance with
appropriatevalues of the standard normal distribution. 530. 344. DECISION RULE.
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975 is 11 . Observatio nGroup Rank1. Shizophrenia, 2 ( 1972), 67-74.
Segal, and Joseph W.
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630. 623. 843. a.
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. 8, the value 0f T
for /2 = 0. THANKS YOULINK FOR THE YOUTUBE VIDEO: http://youtu. We wish to know whether the
dispersion with respect to the variable of interest is different in
the two populations represented by these samples.
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,and Robert A. 8yyyyyyyxxyy1234567891010Observation Group Rank39. On combining the two samples and ranking, we
have the results shown in table 2. 8Untreated (x)Prapanolol treated, 50mg/kg,iv (y)44. 97xxyyxyyxy1234543213. 330.
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362. 3,2,1. 445. 025 is 16 while the value of T for 1-/2 = 0. We reject H0 if T is greater than
the critical value of x.
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be/HZK63vEOaKACopyright © 2022 VDOCUMENTS
. T = Ri, in
other word T is the sum of ranksassigned to the X values. .